Year 8 Maths — Compound interest
Work out compound interest and the amount it grows to, and use the same idea for growth and depreciation.
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1.A machine worth $20000 loses 10 per cent of its value every year. What is it worth after 2 years? Give just the number.
2.$8000 is invested at 5 per cent per year, compounded yearly, for 2 years. What amount does it grow to? Give just the number.
3.$4000 is lent at 10 per cent per year, compounded half-yearly, for 1 year. What amount is owed at the end? Give just the number.
4.A town of 10000 people grows by 10 per cent every year. How many people live there after 2 years?
5.The simple interest on $4000 at 10 per cent for 2 years is $800. What is the compound interest on the same sum at the same rate and time? Give just the number.
6.$1000 is invested at 10 per cent per year, compounded yearly. Match each length of time to the amount it grows to.
- 1 year
- 2 years
- 3 years
- 4 years
- 5 years
- $1100
- $1610.51
- $1464.10
- $1210
- $1331
7.$2000 is invested at 10 per cent per year, compounded yearly, for 3 years. What amount does it grow to? Give just the number.
8.Each card is a rate at which $1000 is invested for 2 years, compounded yearly. Put them in order by the amount at the end, smallest first.
- 8 per cent per year
- 20 per cent per year
- 15 per cent per year
- 10 per cent per year
- 5 per cent per year
Answer key — Year 8 Maths — Compound interest
- 1. 16200
- 2. 8820
- 3. 4410
- 4. 12100
- 5. 840
- 6. 1 year → $1100; 2 years → $1210; 3 years → $1331; 4 years → $1464.10; 5 years → $1610.51
- 7. 2662
- 8. 1. 5 per cent per year 2. 8 per cent per year 3. 10 per cent per year 4. 15 per cent per year 5. 20 per cent per year