Year 10 Computing — Building a list as you go

1.A running total is appended each time round here, so the list holds the totals rather than the values. What does the program print?

totals = []
running = 0
for n in range(1, 5):
    running = running + n
    totals.append(running)
print(totals[3])

2.There are two appends inside this loop rather than one. How many values does the list end up with?

names = []
for n in range(1, 4):
    names.append(n)
    names.append(n * 10)
print(len(names))

3.This program starts with an empty list and puts one value into it each time round. How many values does it end up with?

squares = []
for n in range(1, 5):
    squares.append(n * n)
print(len(squares))

4.The program below is run again with each of these ranges written into its loop heading. Sort each range by how many values the list ends up holding.

kept = []
for n in range(0, 4):
    kept.append(n)

5.This one prints the value that ended up at the front of the list. What does it print?

squares = []
for n in range(1, 6):
    squares.append(n * n)
print(squares[0])

6.This test lets some of the counter's values through and stops the rest. How many values does the list end up with?

kept = []
for n in range(0, 10):
    if n > 6:
        kept.append(n)
print(len(kept))

7.The program below is run again with each of these ranges written into its loop heading. Match each range to the value that ends up last in the list.

made = []
for n in range(0, 4):
    made.append(n * 3)

8.Only some of the counter's values get into this list. What does the program print?

found = []
for n in range(1, 8):
    if n * n > 20:
        found.append(n)
print(found[0])

• a) 6
• b) 5
• c) 4
• d) 25