Year 11 Computing — Looping over a dictionary

1.A loop adds every value of a dictionary into a total that starts at 0. Sort each dictionary by the total that loop reaches.

2.There is a decision inside this loop, so not every key adds to the counter. What does the program print?

sales = {"north": 12, "south": 30, "east": 5, "west": 22}
busy = 0
for place in sales:
    if sales[place] > 20:
        busy = busy + 1
print(busy)

3.A dictionary is built from scratch inside this loop, and one thing in the list turns up twice. What does the program print?

counts = {}
for word in ["pen", "bag", "pen"]:
    counts[word] = 1
print(len(counts))

4.Only the values that get past the comparison reach the total here. What does the program print?

hours = {"mon": 3, "tue": 8, "wed": 2, "thu": 9}
long = 0
for day in hours:
    if hours[day] >= 8:
        long = long + hours[day]
print(long)

5.A program sets total to 0 and then runs "for k in prices:" over the dictionary {"pen": 5, "bag": 10, "cup": 15}, with one of these lines as the body. Match each body to what total holds at the end.

6.This loop prints as it goes, and a dictionary is walked in the order its pairs were written. What is the last number it prints?

sizes = {"small": 2, "large": 7}
for name in sizes:
    print(sizes[name])

7.Every value in this dictionary is added into a running total. What does the program print?

stock = {"pen": 4, "book": 9, "bag": 2}
total = 0
for key in stock:
    total = total + stock[key]
print(total)

8.A loop counts how many of a dictionary's values are over 10. Put these dictionaries in order of that count, fewest first.

• {"pen": 15, "bag": 20, "cup": 30}
• {"pen": 12, "bag": 3}
• {"pen": 4, "bag": 2}
• {"pen": 11, "bag": 40, "cup": 2}