Class 10 Science — Reflection and refraction of light
Apply the New Cartesian Sign Convention to the mirror and lens formulae, work out magnification and the power of a lens, and read a refractive index for what it says about the speed of light.
Name: ________________________
1.Under the New Cartesian Sign Convention, why does the object distance come out negative?
- a) The object is below the principal axis
- b) Object distances are measured from the centre of curvature
- c) The object is placed to the left of the mirror, and distances to the left of the pole count negative
- d) The object is closer to the mirror than the image is
2.For a concave mirror, match each position of the object to where the image forms.
- Object at infinity
- Object beyond C
- Object at C
- Object between C and F
- Image beyond C
- Image at the focus F
- Image at C
- Image between F and C
3.For that same lens the image distance is v = +30 and the object distance is u = -15. Magnification for a lens is m = v/u. What is m? Answer with a number, sign included.
4.A lens has a focal length of 0.5 metres. Power is the reciprocal of the focal length in metres. What is its power, in dioptres? Answer with a number.
5.The refractive index of water is 1.33. What does that number say?
- a) Water is 1.33 times as dense as air
- b) A ray bends through 1.33 degrees on entering water
- c) Light travels 1.33 times as fast in water as it does in air
- d) Light travels 1.33 times as fast in air as it does in water
6.Sort each arrangement by the kind of image it gives.
Groups: Real and inverted · Virtual and erect
- Object between the pole and the focus of a concave mirror
- Object beyond the centre of curvature of a concave mirror
- Object between the centre of curvature and the focus of a concave mirror
- Object at the centre of curvature of a concave mirror
- Object anywhere in front of a convex mirror
7.An optician puts two lenses in contact in a testing frame, one of power +2.0 D and one of +0.25 D. What is the power of the combination?
- a) +2.0 D
- b) +2.25 D
- c) +0.5 D
- d) +1.125 D
8.An object sits at u = -15 in front of a convex lens whose focal length is f = +10. Use 1/v = 1/f + 1/u to find the image distance v. Answer with a number, sign included.
Answer key — Class 10 Science — Reflection and refraction of light
- 1. c) The object is placed to the left of the mirror, and distances to the left of the pole count negative
- 2. Object at infinity → Image at the focus F; Object beyond C → Image between F and C; Object at C → Image at C; Object between C and F → Image beyond C
- 3. -2
- 4.
- 2
- +2
- 5. d) Light travels 1.33 times as fast in air as it does in water
- 6. Object beyond the centre of curvature of a concave mirror → Real and inverted; Object at the centre of curvature of a concave mirror → Real and inverted; Object between the centre of curvature and the focus of a concave mirror → Real and inverted; Object between the pole and the focus of a concave mirror → Virtual and erect; Object anywhere in front of a convex mirror → Virtual and erect
- 7. b) +2.25 D
- 8.
- 30
- +30