Grade 9 Math — Factorisation
Break an algebraic expression into factors, and use those factors to divide one expression by another.
Name: ________________________
1.What is the highest common factor of the two terms in 12x + 18?
2.Sort each expression by the method that factorizes it.
Groups: Take out a common factor · Use a² - b² = (a - b)(a + b)
- 7x + 21
- 9a² - 4b²
- 12m + 18n
- x² - 1
- 5y² - 15y
- x² - 25
3.x² + 7x + 12 factorizes as (x + 3)(x + ?). What number belongs in place of the question mark?
4.Take a out of a² + ab as a common factor. What is left inside the bracket?
5.Which of these is x² + 10x + 25 written in factorized form?
- a) (x + 5)²
- b) (x + 10)²
- c) (x + 5)(x - 5)
- d) (x + 25)(x + 1)
6.Which of these is 4x² - 9 written in factorized form?
- a) (2x - 3)(2x - 3)
- b) (4x - 3)(x + 3)
- c) (2x - 9)(2x + 1)
- d) (2x - 3)(2x + 3)
7.Put these expressions in order by the highest common factor of their terms, smallest first.
- 14x + 21
- 6x + 18
- 10x + 25
- 4x + 8
- 3x + 9
8.Match each expression to its factorized form.
- x² - 16
- x² + 8x + 16
- 3x + 12
- x² - 4x
- 2x² - 32
- (x + 4)²
- (x - 4)(x + 4)
- x(x - 4)
- 3(x + 4)
- 2(x - 4)(x + 4)
Answer key — Grade 9 Math — Factorisation
- 1. 6
- 2. 7x + 21 → Take out a common factor; x² - 25 → Use a² - b² = (a - b)(a + b); 5y² - 15y → Take out a common factor; 9a² - 4b² → Use a² - b² = (a - b)(a + b); 12m + 18n → Take out a common factor; x² - 1 → Use a² - b² = (a - b)(a + b)
- 3. 4
- 4. a + b
- 5. a) (x + 5)²
- 6. d) (2x - 3)(2x + 3)
- 7. 1. 3x + 9 2. 4x + 8 3. 10x + 25 4. 6x + 18 5. 14x + 21
- 8. x² - 16 → (x - 4)(x + 4); x² + 8x + 16 → (x + 4)²; 3x + 12 → 3(x + 4); x² - 4x → x(x - 4); 2x² - 32 → 2(x - 4)(x + 4)